Question 4

Section A · 1 mark · 55% correct

The question in our own words · page 4

For a real parameter \(k\), the pair of equations \(kx+3y=k^2\) and \(2x+(2k+1)y=6-2k\) is solved for \(x\) and \(y\). For which value(s) of \(k\) are there no real solutions?

  1. A\(k=-2\) only
  2. B\(k=\tfrac32\) only
  3. C\(k=-2\) or \(k=\tfrac32\)
  4. Devery real \(k\) except \(-2\) and \(\tfrac32\)
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