M1
2 marks · average 0.5 72% scored 0
The question in our own words · page 25
From part i, the tangent at \(x=p\) is \(t(x)=\cos(p)(x-p)+\sin(p)+1\). As \(p\) moves between \(0\) and \(\tfrac{5\pi}{2}\), how low and how high can the tangent’s \(y\)-intercept go?
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