M1
3 marks · average 1.5 22% scored 0
The question in our own words · page 16
The line \(y=\tfrac{x}{2}+7\) and the curve \(y=Ae^{kx}\) meet at \((-12,1)\) and \((2,8)\). Use the two points to write two equations in \(A\) and \(k\), then solve them by hand to prove that \(A=2^{18/7}\) and \(k=\tfrac{3}{14}\log_e(2)\).
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